16^(5-4x)=1/8^(6-2x)

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Solution for 16^(5-4x)=1/8^(6-2x) equation: 



16^(5-4x)=1/8^(6-2x)

We move all terms to the left:

16^(5-4x)-(1/8^(6-2x))=0



Domain of the equation: 8^(6-2x))!=0

x∈R



We add all the numbers together, and all the variables

16^(-4x+5)-(1/8^(-2x+6))=0

We multiply all the terms by the denominator


(16^(-4x+5))*8^(-2x+6))-(1=0

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